The Internet is full of wonderful information. And as everybody knows, all of it is true. That's why I have almost no hesitation to bring you this factoid I found via "Ask.com":
The statistical chances of a pitcher throwing a no-hitter against a team full of hitters with a .250 average is 0.0004%.
That's based on the premise that a pitcher has a 75% chance of getting each batter out. That works out to a 42% chance of throwing a no-hit inning. Multiply .42 nine times, and you get about 0.0004%. I even checked the math on my own calculator.
It really gives me a new appreciation for Justin Verlander's feat on Tuesday, and explains why these things happen to a team once in a generation. But there's no explanation for why Virgil Trucks threw two no-hitters for the Tigers in 1952 -- he only had 5 wins all year!!!
This calculation doesn't work for perfect games, of course, because batting averages exclude a number of events, such as being hit by a pitch, walks, errors, sacrifice flies, etc.
I got this from a page that appears to be lecture notes from a course syllabus on probabilities, and it includes some interesting factiods on poker, too.
Friday, June 15, 2007
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2 comments:
I wonder what percentage of MLB pitching outings turn out to be no-hitters. How close is it to 0.0004%?
See my reply to your question in my follow-up post:
http://woods-arboretum.blogspot.com/2007/06/no-hitter-corrections-and-further.html
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